Answer:
20 bicycles and 10 tricycles.
Step-by-step explanation:
Let the number of bicycles and tricycles be x and y respectively.
Each vehicle has 1 seat. Each bicycle 2 wheels and each tricycle 3 wheels.
Then we have the system of equations:
x + y = 30 ............ (1)
2x + 3y = 70.........(2)
Multiply the first equation by -2:
-2x - 2y = -60......(3)
Adding (2) + (3):
y = 10
Substituting for y in equation (1):
x + 10 = 30
x = 20.
By simultaneous equation, there are a total of 20 bicycles and 10 tricycles.
Let the number of bicycles and tricycles be x and y respectively.
It is given that there is a total of 30 seats and 70 wheels.
Each vehicle has 1 seat. Each bicycle 2 wheels and each tricycle 3 wheels.
Then we have the system of simultaneous equations:-
x + y = 30 ............ (1)
2x + 3y = 70.........(2)
Multiply the first equation by -2:
-2x - 2y = -60......(3)
Adding (2) + (3):
y = 10
Substituting for y in equation (1):
x + 10 = 30
x = 20.
Therefore, by simultaneous equation, there are a total of 20 bicycles and 10 tricycles.
To learn more about simultaneous equation, refer -
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