Answer:
[tex]\large\boxed{\dfrac{x^2-x}{2x-2x^2}=-\dfrac{1}{2}}[/tex]
Step-by-step explanation:
[tex]\dfrac{x^2-x}{2x-2x^2}=\dfrac{x^2-x}{-2(x^2-x)}\\\\\text{cancel}\ (x^2-x)\\\\=-\dfrac{1}{2}[/tex]
