If we cal lthe first number 'n' then we know that the numbers are n, n+1 and n+2 and we know the sum:
[tex]n+(n+1)+(n+2)=267[/tex]
therefore:
[tex]3n+3=267[/tex]
[tex]3n=264[/tex]
[tex]n=88[/tex]
The numbers are 88,89,90, the largest of which is 90.
To check: 88+89+90=267. Checks.
