Hope this helps :)
Okay so first just keep in mind the trig formulas
Sintheta= perpendicular/hypotenuse
Costheta=base/hypotenuse
Tantheta= perpendicular/base
Just remember it by " some people have curly brown hair through proper brushing"
And the Pythagorean Theorem
Perpendicular^2+Base^2=Hypotenuse^2
Okay so now our base length is x and perpendicular length is y and hypotenuse is [tex]\sqrt{x^2+y^2}[/tex]
for the first three just add the information above in the answer
a) [tex]\frac{y}{\sqrt{x^{2}+y^{2}}}[/tex]
b)[tex]\frac{x}{\sqrt{x^2+y^2}}[/tex]
c)[tex]\frac{y}{x}[/tex]
For the last three, I personally havent done them properly yet but you just reverse the formula if that makes sense
Csctheta=hypotenuse/perpendicular
Sectheta=hypotenuse/base
Cottheta=base/perpendicular
so just add the values we have for base, perpendicular and hypotenuse to these formulas now
d)[tex]\frac{\sqrt{x^2+y^2} }{y}[/tex]
e)[tex]\frac{\sqrt{x^2+y^2}}{x}[/tex]
f)[tex]\frac{x}{y}[/tex]
