Answer:
Step-by-step explanation:
For this problem, point slope form would be the easiest.
Point Slope Form- y-y1 = m(x-x1)
In this case, y1 is 3, x1 is 5, and m would be the slope which is -4.
y-3=-4(x-5)
This is how to write an equation for the problem.
Answer:
[tex]\large{\boxed{y-3=-4(x-5)-\text{point-slope form}}\\\boxed{y=-4x+23}}[/tex]
Step-by-step explanation:
The equation of a line in point-slope form:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point
We have the slope m = -4 and the point (5, 3). Substitute:
[tex]y-3=-4(x-5)[/tex] use distributive property
[tex]y-3=-4x+(-4)(-5)[/tex]
[tex]y-3=-4x+20[/tex] add 3 to both sides
[tex]y=-4x+23[/tex]
