Respuesta :

carlosego

Answer: The first option.

Step-by-step explanation:

You have the following functions:

[tex]r(x)=3x-1\\s(x)=2x+1[/tex]

You have that [tex](\frac{r}{2})[/tex] indicates the following:

[tex](\frac{r}{s})=\frac{3x-1}{2x+1}[/tex]

Now, you must substitute x=6, then you obtain:

[tex](\frac{r}{s})(6)=\frac{3(6)-1}{2(6)+1}[/tex]

Therefore the answer is the first option.

zainebamir540

Answer:

Choice A is correct answer.

Step-by-step explanation:

We have given two functions.

r(x) = 3x – 1 and s(x) = 2x + 1

We have to find the quotient of the given two functions.

(r/s)(x) = ?    and (r/s)(6) = ?

The formula to find the quotient is:

(r/s)(x) = r(x) / s(x)

Putting given values in above formula, we have

(r/s)(x) = 3x-1 / 2x-1

Putting x   6 in above equation, we have

(r/s)(6) = 3(6)-1 / 2(6)-1 which is the answer.

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