I WILL GIVE BRAINESTWhat is the area of Figure ABCD?


A trapezoid ABCD is drawn with length of parallel sides AB and CD equal to 14 inches and 18 inches, respectively. The length of one of the non-parallel sides BC is 7 inches. Side BC is perpendicular to DC. A perpendicular line drawn from A to side CD meets CD at E.


84 square inches

98 square inches

105 square inches

112 square inches

I WILL GIVE BRAINESTWhat is the area of Figure ABCDA trapezoid ABCD is drawn with length of parallel sides AB and CD equal to 14 inches and 18 inches respective class=

Respuesta :

Answer: 112 square inches


Step-by-step explanation:

The area of trapezoid is given by :-

[tex]\text{Area}=\frac{1}{2}\times(a+b)h[/tex], where a and b are the opposite parallel sides and h is the height of the trapezoid.

From the given picture the area of trapezoid ABCD with height 7 inches and opposite parallel sides 14 inches and 18 inches is given by:-

[tex]\text{Area}=\frac{1}{2}\times(14+18)7\\\Rightarrow\text{Area}=\frac{1}{2}(32)(7)\\\Rightarrow\ \text{Area}=16\times7\\\Rightarrow\text{Area}=112\ inches^2[/tex]

Answer:

D. [tex]112\text{ in}^2[/tex]

Step-by-step explanation:

We have been given an image of a trapezoid. We are asked to find the area of our given trapezoid.

[tex]\text{Area of trapezoid}=\frac{1}{2}*(\text{Sum of parallel sides})*\text{Height}[/tex]

Since side BC is perpendicular to DC, so height of trapezoid will be equal to BC that is 7 inches.

Upon substituting our given values in above formula, we will get:

[tex]\text{Area of trapezoid}=\frac{1}{2}*(\text{14 in+18 in})*\text{7 in}[/tex]

[tex]\text{Area of trapezoid}=\frac{1}{2}*(\text{32 in})*\text{7 in}[/tex]

[tex]\text{Area of trapezoid}=\text{16 in}*\text{7 in}[/tex]

[tex]\text{Area of trapezoid}=112\text{ in}^2[/tex]

Therefore, the area of our given trapezoid is 112 square inches and option D is the correct choice.