Answer:
(3,13)
Step-by-step explanation:
[tex]y=x^2-6x+22\\y=x^2-6x+22+3^2-3^2\\y=(x-3)^2+22-9\\y=(x-3)^2+13[/tex]
Note that by vertex form we have:
[tex]y=a(x-h)^2+k[/tex]
Where the vertex has the coordinates (h,k) so we change the sign of h and keep the same k value and so:
h=3 and k=13
Therefore the vertex of this parabola is: (3,13)
