Answer: 25.7 mol
From the balanced reaction, 2 mol of Octane produces 18 mol of Water.
Find the moles of Octane you are reacting.
moles of Octane = mass of Octane/ molar mass = 325g/ 114.23 g/mol = 2.85 mol.
Since Oxygen is in excess, limiting reagent is Octane.
2 mol Octane produces 18 mol Water.
1mol Octane produces 9 mol Water.
Therefore, 2.85 mol Octane will produce Water = 2.85 mol Octane x 9 mol Water/ 1mol Octane
= 25.7 mol
