Here if we assume that there is no air friction on both balls then we can say
[tex]F = mg[/tex]
now the acceleration is given as
[tex]F = ma = mg[/tex]
[tex]a = g[/tex]
so here both the balls will have same acceleration irrespective of size and mass
so we can say that to find out the time of fall of ball we can use
[tex]y = \frac{1}{2}gt^2[/tex]
[tex]t = \sqrt{\frac{2y}{g}}[/tex]
now from above equation we can say that time taken to hit the ground will be same for both balls and it is irrespective of its mass and size