Joanne has a cylindrical, above ground pool. the depth (height) of the pool is 1/2 of its radius, and the volume is 1570 cubic feet. What is the area of its bottom floor? Include equations or inequalities related.

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frika

Answer:

[tex]\sqrt[3]{3140^2\pi}\approx 146.41\ ft^2[/tex]

Step-by-step explanation:

The volume of the cylinder is

[tex]V_{cylinder}=\pi r^2\cdot H,[/tex]

where r is the base radius and H is the height.

Since [tex]H=\dfrac{1}{2}r[/tex] and V=1570 cubic feet, then

[tex]1570=\pi r^2\cdot \dfrac{r}{2},\\ \\1570=\dfrac{\pi r^3}{2},\\ \\r^3=\dfrac{3140}{\pi},\\ \\r=\sqrt[3]{\dfrac{3140}{\pi}}\ ft.[/tex]

The area of its bottom floor is

[tex]A_{floor}=\pi r^2=\pi\cdot \left(\sqrt[3]{\dfrac{3140}{\pi}}\right)^2= \sqrt[3]{3140^2\pi}\approx 146.41\ ft^2.[/tex]