1st expression is [tex]\dfrac{2}{3}(122+98),[/tex] because
- the sum of 122 and 98 is 122+98=220;
- Two-thirds of the sum of 122 and 98 is [tex]\dfrac{2}{3}(122+98)=\dfrac{440}{3}=146\dfrac{2}{3}.[/tex]
2nd expression is [tex]\dfrac{99}{10}\cdot (84+3),[/tex] because
- the sum of 84 and 3 is 84+3;
- 99 divided by 10 is [tex]\dfrac{99}{10};[/tex]
- 99 divided by 10, then multiplied by the sum of 84 and 3 is [tex]\dfrac{99}{10}\cdot (84+3)=\dfrac{99}{10}\cdot 87=\dfrac{8,613}{10}=861.3[/tex]
3. If compare these two expressions, then
[tex]\dfrac{2}{3}(122+98)<\dfrac{99}{10}\cdot (84+3).[/tex]
