Part a)
kinetic energy of the hammer will be
[tex]KE = \frac{1}{2} mv^2[/tex]
here we know that
m = 4 kg
v = 6 m/s
now by the equation of kinetic energy we have
[tex]KE = \frac{1}{2}*4 * 6*6[/tex]
[tex]KE = 72 J[/tex]
Part b)
for finding the force we will have
[tex]v_f^2 - v_i^2 = 2 a d[/tex]
here we know that
[tex]v_f = 0[/tex]
[tex]v_i = 6 m/s[/tex]
[tex]d = 10 cm = 0.10 m[/tex]
now from above equation we have
[tex]0 - 6^2 = 2 * a * 0.10[/tex]
[tex]a = -180 m/s^2[/tex]
now by Newton's II law we have
[tex]F = ma[/tex]
[tex]F = 4*180 = 720 N[/tex]
so it requires 720 N.