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Suppose you deposit $2,000 in a savings account that pays interest at an annual rate of 4%. If no money is added or withdrawn, determine how much would be in the account after 18 years.

Respuesta :

Answer

A=p (1+r)^t

A future value

P present value

R interest rate

T time


A) A=2,000×(1+0.04)^(3)=2,249.728


B) A=2,000×(1+0.04)^(18)=4,051.63


C) 2500=2000 (1+0.04)^t

Solve for t

T=log(2,500÷2,000)÷log(1+0.04)

T=5.7 years


D) t=log(3,000÷2,000)÷log(1+0.04)

t=10.3 years