Answer:
Option G is right.
Step-by-step explanation:
Given that 2x^2+6x =36
To find possible values of x, let us use factorisation method.
First divide the equation by 2, x^2+3x-18 =0
Factors are (x+6)(x-3)
Equate each factor to 0
x+6 =0 or x-3=0
x =-6 or 3
Hence values of x are -6 and 3.
