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27-10-2018
Mathematics

contestada

find an equation that meets the conditions p varies inversely as d, and p = 2 when d = 3

Respuesta :

ifeoluwaakinrip6qdgr ifeoluwaakinrip6qdgr

27-10-2018

Answer:

pd = 6

Step-by-step explanation:

p ∝ 1/d

change ∝ to = by adding constant k or c

p = k * 1/d

p = k/d

Cross multiply

pd = k

k = pd

k = 2 * 3

k = 6

From pd = k

pd = 6

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