Given: 72% of the population shows D trait.
To find: The frequency of allele for the d trait.
Method: Use of Hardy-Wineberg equation at equilibrium to solve it.
Solution:
Let p denote the frequency of D trait allele and q denote the frequency of the d trait allele.
p + q = 1
(p + q)² = 1
p² + 2pq + q² = 1
or q² = 1 - (p² + 2pq)
Since D is a dominant trait, it'll be expressed in both the homozygous and heterozygous individuals that make up 72% of the population.
∴ (p² + 2pq) = [tex]\frac{72}{100}[/tex] = 0.72
∴ q² = 1 - 0.72 = 0.28
q = √0.28 = 0.53
Hence the frequency of the recessive d trait is given by q = 0.53.
Answer:
72% of the population shows D trait.
To find: The frequency of allele for the d trait.
Method: Use of Hardy-Wineberg equation at equilibrium to solve it.
Solution:
Let p denote the frequency of D trait allele and q denote the frequency of the d trait allele.
p + q = 1
(p + q)² = 1
p² + 2pq + q² = 1
or q² = 1 - (p² + 2pq)
Since D is a dominant trait, it'll be expressed in both the homozygous and heterozygous individuals that make up 72% of the population.
∴ (p² + 2pq) = = 0.72
∴ q² = 1 - 0.72 = 0.28
q = √0.28 = 0.53
Hence the frequency of the recessive d trait is given by q = 0.53.
Explanation:
