Answer: 1.2 s
It is given that a ball is thrown vertically upwards with initial velocity, u= 12 m/s.
At the maximum height, instantaneous velocity would be, v= 0 m/s
the ball would decelerate due to gravity, [tex]g=-9.8m/s^{2}[/tex]
using equation of motion,
[tex]v-u=gt\\ \Rightarrow t=\frac{v-u}{g} \\ \Rightarrow t= \frac {0-12 m/s}{9.8 m/s^{2}}=1.2s[/tex]
Hence, the time taken by ball to reach its maximum height is 1.2 s when thrown vertically upward with initial velocity of 12 m/s.
