Solution: 85.11 m
Given:
acceleration of the car, [tex]a= 0.85 m/s^{2}[/tex]
initial velocity,[tex]u=83km/h=23.05 m/s[/tex]
final velocity, [tex]v=94 km/h=26.11 m/s[/tex]
we need to find the displacement (s) of the car.
we would use the equation of motion:
[tex] 2as=v^{2}-u^{2}\\ \Rightarrow s=\frac{v^{2}-u^{2}}{2a} \\ \Rightarrow s=\frac{26.11^{2}-23.05^{2}}{2\times0.85}\\ \Rightarrow s=85.11 m[/tex]
hence, the displacement done by the car is = 85.11 m
