Respuesta :
[tex] |\Omega|=C(52,2)=\dfrac{52!}{2!50!}=\dfrac{51\cdot52}{2}=1,326\\
|A|=26\cdot26=676\\\\
P(A)=\dfrac{676}{1,326}=\dfrac{26}{51}\approx51\% [/tex]
[tex] |\Omega|=C(52,2)=\dfrac{52!}{2!50!}=\dfrac{51\cdot52}{2}=1,326\\
|A|=26\cdot26=676\\\\
P(A)=\dfrac{676}{1,326}=\dfrac{26}{51}\approx51\% [/tex]