A partial cylinder lies on its side. The bases are a 90� sector of a circle. What is the exact volume of the partial cylinder?

As the partial cylinder is one fourth of the regular cylinder ,
So the formula for volume is given by
[tex] V= \frac{1}{4} \pi r^{2} h [/tex]
Plugging all the values we get
[tex] V= \frac{1}{4} \pi (8)^{2} (10) = \frac{1}{4} \pi *64 * 10 = 160\pi [/tex] [tex] in^3 [/tex]
Answer:
160π[tex]in^{3}[/tex]
Step-by-step explanation:
Since,wearegiven a partial cylinder, therfore volume of the partial cylinder will be:
V= [tex]\frac{1}{4} \pi r^{2}h[/tex]
V= [tex]\frac{1}{4} \pi 8^{2} (10)[/tex] (r= 8in and h= 10in)
V= [tex]\frac{1}{4} \pi (64)(10)[/tex]
V= 160π [tex]in^{3}[/tex]