Respuesta :
For the given sequence 2n-1,
Let n=1 , so the first term of the sequence = [tex] (2 \times 1) -1 =1 [/tex]
For n=2, the second term of the sequence= [tex] (2 \times 2) -1 =3 [/tex]
For n =3, the third term of the sequence = [tex] =(2 \times 3) -1 =5 [/tex]
Similarly, for n= 19, the last term of the sequence = [tex] (2 \times 19) -1 =37 [/tex]
Therefore, the sequence is [tex] 1,3,5,7,....37 [/tex]
Since the common difference of the sequence formed is 2 which is same throughout the sequence. Hence, it forms an arithmetic progression.
Sum of arithmetic progression is given by = [tex] \frac{n}{2}(a+l) [/tex]
where 'a' is the first term and 'l' is the last term of the given sequence.
Sum= [tex] \frac{19}{2}(1+37) [/tex]
=[tex] 361 [/tex]
