The sample mean is μ=105, and sample standard deviation is σₓ=[tex] \frac{σ}{\sqrt{n}} =\frac{10}{\sqrt{25}} =2 [/tex].
The Z-score is [tex] Z=\frac{ 107.8-105}{2}=1.4 [/tex].
Refer to standard normal distribution table.
The required probability is
[tex] P(X>107.8)=P(Z>1.4)=1-P(Z<1.4)=0.0808 [/tex]
