Respuesta :

you move the x^-4 down and it becomes positive

so the answer is C
gmany

[tex] a^{-n}=\dfrac{1}{a^n}\\------------\\\\\dfrac{2x^{-4}}{3xy}=\dfrac{2}{3xy}\cdot\dfrac{1}{x^4}=\dfrac{2}{3x^5y}\to C. [/tex]

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