Use the discriminant to determine the number and type of solutions for the following equation. 2x2 + 14x + 11 = 0

A) there are zero rational solutions
B) there is one rational solution
C) there are two rational solutions
D) there are two irrational solutions

Respuesta :

[tex] \bf \qquad \qquad \qquad \textit{discriminant of a quadratic}
\\\\\\
\stackrel{\stackrel{a}{\downarrow }}{2}x^2\stackrel{\stackrel{b}{\downarrow }}{+14}x\stackrel{\stackrel{c}{\downarrow }}{+11}
~~~~~~~~
\stackrel{discriminant}{b^2-4ac}=
\begin{cases}
0&\textit{one solution}\\
\underline{positive}&two~\stackrel{rational}{solutions}\\
negative&\textit{no solution}
\end{cases}
\\\\\\
14^2-4(2)(11)\implies 108\impliedby \underline{positive} [/tex]