(x²-15x+56)/(x-7)
first we can factor out the numerator
x²-15x+56
we need to find a number that multiplies together to equal 56 and also adds together to equal -15
-8 and -7 fit into this criteria
x²-7x-8x+56
now we take out our common factors
x(x-7)-8(x-7)
we take the two values outside and the values inside and that is our factored form
(x-8)(x-7)
now our fraction is
[tex] \frac{(x-8)(x-7)}{(x-7)} [/tex]
since it is on the numerator and the denominator, we can cancel out (x-7)
so now we are left with our answer:
x-8
hope this helped!
