You apply a horizontal force of 10.0 N to pull a wheeled suitcase at a constant speed of 0.5 m/s across flat ground. How much power is used?

Respuesta :

[tex]P=\frac{dW}{dt}=\frac{d}{dt}(Fr)=F\frac{dr}{dt}=Fv[/tex]

[tex]P=Fv[/tex]
[tex]P=(10.0N)(0.5\frac{m}{s})[/tex]
[tex]P=\frac{5N-m}{s}[/tex]
[tex]P=\frac{5J}{s}[/tex]
[tex]P=5W[/tex]