From the equation
[tex] {x}^{2} - 10x + 25 = 0[/tex]
We can see that 25 is 5 × 5, and 10 is 5 + 5, so the equation simplifies to
[tex](x - 5)(x - 5) = 0 \\ {(x - 5)}^{2} = 0[/tex]
which then we use to set each parentheses to equal 0
[tex](x - 5) = 0 \\ x = 5[/tex]
Since both parentheses are the same, there is only one solution: C. 1 real number solution
