[tex]F(x)+\left(\dfrac{2}{5}\right)^x[/tex]
C. The y-intercept is (0, 1)
[tex]f(0)=\left(\dfrac{2}{5}\right)^0=1\to(0,\ 1)[/tex]
D. The range of F(x) is y > 0
[tex]F(x)=\left(\dfrac{2}{5}\right)^x > 0\ for\ x\in\mathbb{R}[/tex]
E. It is decreasing
[tex]f(x)=a^x\\if\ a > 1\ then\ is\ increasing\\if\ a\in(0;\ 1)\ then\ is\ decreasing\\\\F(x)=\left(\dfrac{2}{5}\right)^x\to a=\dfrac{2}{5}\in(0;\ 1)[/tex]
A. Not, because the domain is all real numbers
B. Not, because it is decreasing.
F. Not, because the x-intercept is not exist.
