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In the reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O, an equivalence point occurs when 18.45 mL of 0.1953 M NaOH is added to a 21.25 mL portion of H2SO4. What is the [H2SO4]?

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tаskmasters
The solution is found using chemistry techniques.
            moles NaOH = c · V = 0.1953 mmol/mL · 18.45 mL = 3.603285 mmol
            moles H2SO4 = 3.603285 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 1.8016425 mmol
Hence
            [H2SO4]= n/V = 1.8016425 mmol / 21.25 mL = 0.08478 M
The answer to this question is  [H2SO4] = 0.08478 M