Respuesta :
So attached is a picture of the triangle you are talking about and listed under are the choices:
A.) Cos Z=b/c
B.) Sin X=c/b
C.) Tan X=b/a
D.) Tan Z=a/b
The answer would then be B. SinX = c/b.
Just remember SOH CAH TOA:
Sinθ= Opposite Cosθ = Adjacent Tanθ= Opposite
Hypotenuse Hypotenuse Adjacent
Using the triangle in the scenario, you just need to identify which side is which.
Given m∠Z
Adjacent = b
Opposite = a
Hypotenuse = c
SinZ= a CosZ = b TanZ= a
c c b
Given m∠X:
Adjacent = b
Opposite = a
Hypotenuse = c
SinX= b CosX = a TanX= b
c c a
So the answer is B.
Attached is a picture of how I assigned the sides depending on the angle used.
A.) Cos Z=b/c
B.) Sin X=c/b
C.) Tan X=b/a
D.) Tan Z=a/b
The answer would then be B. SinX = c/b.
Just remember SOH CAH TOA:
Sinθ= Opposite Cosθ = Adjacent Tanθ= Opposite
Hypotenuse Hypotenuse Adjacent
Using the triangle in the scenario, you just need to identify which side is which.
Given m∠Z
Adjacent = b
Opposite = a
Hypotenuse = c
SinZ= a CosZ = b TanZ= a
c c b
Given m∠X:
Adjacent = b
Opposite = a
Hypotenuse = c
SinX= b CosX = a TanX= b
c c a
So the answer is B.
Attached is a picture of how I assigned the sides depending on the angle used.

