A certain insect population doubles every 3 days. Suppose that currently, there are 50 insects in the colony. How many insects will be in the colony in 3 weeks.
A- 1600
B- 6400
C- 3200
D- 12800
This is exponential growth. We start with 50 insects. In 3 days we have 100 insects (double 50). Therefore,
100 = 50*e^(k*3), where k is the growth constant. log 2 Then 2 = e^(3k), and log 2 = 3k, so that k = ----------- 3 log 2 Formula: N = 50*e{---------- *t} 3
You'll need to evaluate this formula for t=3 (weeks). Can you do that?
