payshencec21
payshencec21
30-05-2018
Mathematics
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please help asap 30 pts
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gmany
gmany
30-05-2018
[tex]\dfrac{x^2+4x-5}{1-x}=\dfrac{x^2+5x-x-5}{-(x-1)}=\dfrac{x(x+5)-1(x+5)}{-(x-1)}\\\\=\dfrac{(x+5)(x-1)}{-(x-1)}=-(x+5)\\\\\boxed{Answer:-x-5}[/tex]
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