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PLZ HELP QUICKLY!!!Find the measure of the acute angle in a rhombus if its side makes with the diagonals angles such that one of them is three times larger than the other.

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clairebear11213
A rhombus has 4 angles. Two obtuse that are equal and two acute that are equal. If all of the angles in a rhombus add up to 360°, then one acute and one obtuse must add up to half that: 180°.
The acute to obtuse angle ratio is 1:3. Think of this as four parts. One part acute, three parts obtuse.
180 ÷ 4 = 45
Therefore, The acute angle is 45°, and the obtuse angle is 135°
MrRoyal

The acute angle in the rhombus is 45 degrees

How to determine the acute angle?

A rhombus have 2 congruent acute angles, and 2 congruent obtuse angles

Represent the angles with x and y.

Where the acute angle is x

The angles add up to 360 degrees.

So, we have:

[tex]2(x + y) = 360[/tex]

Divide both sides by 2

[tex]x +y = 180[/tex]

From the question, we have:

[tex]y = 3x[/tex]

So, the equation becomes

[tex]x + 3x = 180[/tex]

Evaluate the sum

[tex]4x = 180[/tex]

Divide both sides by 4

[tex]x= 45[/tex]

Hence, the acute angle is 45 degrees

Read more about rhombus at:

https://brainly.com/question/20627264

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