Respuesta :

gmany
[tex]y=12^x\ \ \ |log_{12}\\\\\log_{12}y=\log_{12}12^x\\\\\log_{12}y=x\log_{12}12\\\\x=\log_{12}y[/tex]


[tex]y=12^x\to y^{-1}=\log_{12}x;\ x\in\mathbb{R^+}\to\ y^{-1}=\dfrac{\log x}{\log12};\ x\in\mathbb{R^+}\to y^{-1}=\dfrac{\ln x}{\ln 12}[/tex]

[tex]Used:\\\\\log_aa=1\\\\\log_ab^n=n\log_ab\\\\\log_ab=\dfrac{\log_cb}{\log_ca}[/tex]
mathstudent55

Answer:

[tex] y = \dfrac{\log x}{\log 12} [/tex]

Step-by-step explanation:

[tex] y = 12^x [/tex]

[tex] x = 12^y [/tex]

[tex] \log x = \log 12^y [/tex]

[tex] \log x = y \log 12 [/tex]

[tex] y \log 12 = \log x [/tex]

[tex] y = \dfrac{\log x}{\log 12} [/tex]

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