behringer950
behringer950
28-08-2014
Mathematics
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4x < 16 or 12x > 144
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Аноним
Аноним
28-08-2014
[tex]4x < 16\ or\ 12x > 144\\\\x < 16:4\ or\ x > 144:12\\\\x < 4\ or\ x > 12\\\\x\in(-\infty;\ 4)\ \cup\ (12;\ \infty)[/tex]
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