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4.) Based on the following data, what is the standard Gibbs free energy of formation of the chloride ion at 298 K?
(R = 8.314 J/(K · mol))
PbCl2(s) → Pb2+(aq) + 2Cl–(aq);
Ksp = 1.7 × 10–5

∆G°f (kJ/mol) at 298 K
Pb2+(aq) –24.4
PbCl2(s) –314.1

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