A person wearing a parachute jumps out of an airplane. Assume that there is no wind and that the parachute provides viscous damping relative to a fixed reference frame. The parachute has a relatively small mass Mp and a large damping coefficient Bp. The jumper has a larger mass Mj and a smaller drag coefficient Bj. The cords attaching the parachute to the jumper are assumed to be quite springy. The elastic effect of the risers is represented by the constant Kr. A simple equivalent diagram is shown below. ปล W хр xxxxx 40 M, tele KR w x; M; 52 a. Write the modeling equations describing the motions of the jumper and the parachute. Assume Xp and xj are both zero at time t=0. b. Take the positive direction of these displacements at downward, draw a Simulink diagram to solve these equations. Use the following parameters, Mp= 10 Kg, M;= 60 Kg, Bp=100 N.s/m2, and Kr = 400 N/m. c. Simulate the following experiment: The jumper jumps out of the plane and the parachute open Let t=0 be the instant the parachute opens. At this time the rises are fully extended, so they are neither slack nor stretched. Run the simulation and show Xp and x; for the first 5 seconds after the parachute opens. Show also the corresponding velocities, and the riser elongation (xj – Xp).